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Simple Harmonic Motion — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsSimple Harmonic Motion1 Mark
MCQ
A particle executes simple harmonic motion with a frequency $f$. The frequency with which its kinetic energy oscillates is
  • A
    $f / 2$
  • B
    $f$
  • ✓
    $2 f$
  • D
    $4 f$
✓

Answer

Correct option: C.
$2 f$
(c)Kinetic energy $K=\frac{1}{2} m v^2=\frac{1}{2} m a^2 \omega^2 \cos ^2 \omega t$$=\frac{1}{2} m \omega^2 a^2(1+\cos 2 \omega t)$ hence kinetic energy varies periodically with double the frequency of S.H.M. i.e. $2 \omega$.

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