MCQ
A particle is moving along a straight line with increasing speed. Its angular momentum about a fixed point on this line
- AGoes on increasing
- BGoes on decreasing
- CMay be increasing or decreasing depending on direction of motion
- ✓Remains zero
✓
Answer
Correct option: D.
Remains zero
d
$\mathrm{L}=0$ because angle between $\overrightarrow{\mathrm{r}} \& \overrightarrow{\mathrm{v}}$ is always
$\mathrm{L}=0$ because angle between $\overrightarrow{\mathrm{r}} \& \overrightarrow{\mathrm{v}}$ is always
zero (as point lies on the same line)
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