A particle is performing simple harmonic motion along $x$ -axis with amplitude $4\, cm$ and time period $1.2\, sec$. The minimum time taken by the particle to move from $x = 2\, cm$ to $x =+ 4 \,cm$ and back again is given by .... $s$
A$0.6$
B$0.4$
C$0.3$
D$0.2$
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B$0.4$
b minimum time taken by particle $=\frac{T}{6}+\frac{T}{6}$
$=\frac{T}{3}$
$=0.4 \mathrm{s}$
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