MCQ
A particle is projected vertically upwards from $O$ with velocity $v$ and a second particle is projected at the same instant from $P$ (at a height h above $O$) with velocity $v$ at an angle of projection $\theta$ . The time when the distance between them is minimum is
- A$\frac{h}{{2v\sin \,\theta }}$
- B$\frac{h}{{2v\cos \,\theta }}$
- C$h/v$
- ✓$h/2v$
