MCQ
A particle moves along the X-axis as x = u(t - 2s) + a(t - 2s)2.
- AThe initial velocity of the particle is u.
- BThe accelerati?n of the particle is a.
- CThe acceleration of the particle is 2a.
- DAt t = 2s particle is at the origin.
✓
Answer
- The acceleration of the particle is 2a.
- At t = 2s particle is at the origin.
Explanation:
Initial velocity $=\Big|\frac{\text{dx}}{\text{dt}}\Big|_{\text{t} = 0}$
$\frac{\text{dx}}{\text{dt}}=\text{u}+2\text{a}(\text{t}-2\text{s})$
$\Big|\frac{\text{dx}}{\text{dt}}\Big|_{\text{t}=0}=\text{u}-4\text{as}\neq\text{u}$
Acceleration $=\frac{\text{d}^2\text{x}}{\text{dt}^2}=2\text{a}$
At t = 2s,
x = u(2s - 2s) + a(2s - 2s)2 = 0 (origin)
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