MCQ
A particle performs simple harmonic motion with amplitude A along a straight line. The potential energy of the particle will be maximum when its displacement is :
- ✓$\pm A$
- BZero
- C$\pm \frac{A}{2}$
- D$\pm \frac{ A }{\sqrt{2}}$
✓
Answer
Correct option: A.
$\pm A$
(A)
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