MCQ
A pendulum clock that keeps correct time on the earth is taken to the moon it will run (it is given that $g_{Moon} = g_{Earth}/6$ )
- AAt correct rate
- B$6$ time faster
- C$\sqrt 6 $ times faster
- ✓$\sqrt 6 $ times slowly
✓
Answer
Correct option: D.
$\sqrt 6 $ times slowly
d
(d) $T = 2\pi \sqrt {\frac{l}{g}} $==>$\frac{{{T_e}}}{{{T_m}}} = \sqrt {\frac{{{g_m}}}{{{g_e}}}} = \sqrt {\frac{{{g_e}/6}}{{{g_e}}}} = \frac{1}{{\sqrt 6 }}$
(d) $T = 2\pi \sqrt {\frac{l}{g}} $==>$\frac{{{T_e}}}{{{T_m}}} = \sqrt {\frac{{{g_m}}}{{{g_e}}}} = \sqrt {\frac{{{g_e}/6}}{{{g_e}}}} = \frac{1}{{\sqrt 6 }}$
$ \Rightarrow $ ${T_m} = \sqrt 6 {T_e}$ i.e. clock becomes slower.
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