A pendulum is swinging in an elevator. Its period will be greatest when the elevator is
AIIMS 2010, Medium
Download our app for free and get started
Time period of a simple pendulum is given by
$T=2 \pi \sqrt{\frac{l}{g}}$ or $T \propto \sqrt{\frac{l}{g}}$
when the elevator is accelerating downwards, the net gravitational acceleration is $(g-a),$ so, the time period when elevation is accelerating downwards, is greatest.
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionA system is oscillating with undamped simple harmonic motion. Then the
- 2A simple pendulum with length $L$ and mass $m$ of the bob is vibrating with an amplitude $A$. The maximum tension in the string isView Solution
- 3A mass of $5\, {kg}$ is connected to a spring. The potential energy curve of the simple harmonic motion executed by the system is shown in the figure. A simple pendulum of length $4\, {m}$ has the same period of oscillation as the spring system. What is the value of acceleration due to gravity on the planet where these experiments are performed? (In ${m} / {s}^{2}$)View Solution
- 4View SolutionThe mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If it is a second's pendulum on earth)
- 5The energy of a particle executing simple harmonic motion is given by $E = Ax^2 + Bv^2$, where $x$ is the displacement from mean position $x = 0$ and $v$ is the velocity of the particle at $x$ then choose the incorrect statementView Solution
- 6If a simple pendulum oscillates with an amplitude of $50\, mm$ and time period of $2\, sec$, then its maximum velocity is .... $m/s$View Solution
- 7In an experiment for determining the gravitational acceleration $g$ of a place with the help of a simple pendulum, the measured time period square is plotted against the string length of the pendulum in the figure. What is the value of $g$ at the place? ...... $m/s^2$View Solution
- 8The motion of a particle represented by $y\ =$ $\sin \omega t - \cos \omega t$ isView Solution
- 9A ball is rolling without slipping in a spherical shallow bowl (radius $R$ ) as shown in the figure and is executing simple harmonic motion. If the radius of the ball is doubled, then the time period of oscillationView Solution
- 10A particle executing simple harmonic motion with amplitude of $0.1 \,m$. At a certain instant when its displacement is $0.02 \,m$, its acceleration is $0.5 \,m/s^2$. The maximum velocity of the particle is (in $m/s$)View Solution