A point mass oscillates along the x-axis according to the law $x=x_0cos$$\left( {\omega t - \frac{\pi }{4}} \right)$ If the acceleration of the particle is written as $a=Acos$$\left( {\omega t + \delta } \right)$ then
AIEEE 2007, Medium
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$x=x_{0} \cos (\omega t-\pi / 4)$

$\therefore$ Velocity, $v=\frac{d x}{d t}=-x_{0} \omega \sin \left(\omega t-\frac{\pi}{4}\right)$

Acceleration,

$a=\frac{d v}{d t}=-x_{0} \omega^{2} \cos \left(\omega t-\frac{\pi}{4}\right)$

$=x_{0} \omega^{2} \cos \left[\pi+\left(\omega t-\frac{\pi}{4}\right)\right]$

$=x_{0} \omega^{2} \cos \left(\omega t+\frac{3 \pi}{4}\right)$              $...(1)$      

Acceleration, $a=A \cos (\omega t+\delta)$                      $...(2)$

Comparing the two equations, we get

$A=x_{0} \omega^{2}$ and $\delta=\frac{3 \pi}{4}$

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