A pendulum is executing simple harmonic motion and its maximum kinetic energy is $K_1$. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is $K_2$ then
JEE MAIN 2019, Medium
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Maximum kinetic energy at lowest point $B$ is given by
$\mathrm{K}=\mathrm{mg} \ell(1-\cos \theta)$
where $\theta=$ angular amp.
$\mathrm{K}_{1}=\mathrm{mg} \ell(1-\cos \theta)$
$\mathrm{K}_{2}=\mathrm{mg}(2 \ell)(1-\cos \theta)$
$\mathrm{K}_{2}=2 \mathrm{K}_{1}$
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