A potential difference of $5 \,V$ is applied across a conductor of length $10 \,cm$. If drift velocity of electrons is $2.5 \times 10^{-4} \,m / s$, then electron mobility will be ............ $m ^2 V ^{-1} s ^{-1}$
A$5 \times 10^{-4}$
B$5 \times 10^{-6}$
C$5 \times 10^{-2}$
D$0$
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B$5 \times 10^{-6}$
b (b)
$\mu=\frac{V_D}{E}$
$\mu=\frac{2.5 \times 10^{-4} \times 0.1}{5}$
$\mu=5 \times 10^{-6} \,m ^2 V ^{-1} s ^{-1}$
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