$A$ potentiometer wire has length $10\, m$ and resistance $10\,\Omega$ . It is connected to a battery of $EMF$ $11\, volt$ and internal resistance $1\, \Omega$ , then the potential gradient in the wire is ............... $V/m$
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Total resistance $=10+1=11 \Omega$
Current in the circuit $=\frac{11}{11}=1 A$
Potential across the wire $=$ current $\times$ resistance $=10 \mathrm{V}$
since, Potential gradient is equal to potential per meter
Potential Gradient $=\frac{10}{10}=1 V / m$
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