The equivalent resistance between the points $P$ and $Q$ in the network given here is equal to ................ $\Omega$ (given $r = \frac{3}{2}\Omega $)
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(b) The given circuit can be simplifies as follows
$R' = \frac{{2r}}{3} = \frac{2}{3} \times \frac{3}{2} = 1\Omega $.
$R' = \frac{{2r}}{3} = \frac{2}{3} \times \frac{3}{2} = 1\Omega $.
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