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Electromagnetic Induction — Physics STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 SciencePhysicsElectromagnetic Induction2 Marks
Question
A rectangular loop and a circular loop are moving out of a uniform magnetic field with a constant velocity $v$ as shown in the figure :
Image
Magnetic field is perpendicular to the plane of loops. Explain in which loop, the magnitude of induced emf will remain constant while emerging out of magnetic field?
✓

Answer

Rate of change of area $\left(\frac{d A}{d t}\right)$ of rectangular loop, while it is moving out of magnetic field with constant velocity $v$ will remain constant but not for circular loop. Hence according to the formula
$ \varepsilon=-\left(\frac{d \phi_{B}}{d t}\right)=\frac{-d}{d t}(BA)=-B\left(\frac{d A}{d t}\right) $
Induced emf in the rectangular loop will remain constant for $\vec{B}$.

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