A rectangular surface of sides 10 ,cm and 15 ,cm is placed inside… - Vidyadip

MCQ

A rectangular surface of sides $10 \,cm$ and $15 \,cm$ is placed inside acyniform electric field of $25 \,V / m$, such that the surface makes an angle of $30^{\circ}$ with the direction of electric field. Find the flux of the electric field through the rectangular surface .................. $Nm ^2 / C$

A
$0.1675$
✓
$0.1875$
C
$0$
D
$0.1075$

✓

Answer

Correct option: B.

$0.1875$

b
(b)

$\phi=E A \cos 30^{\circ}$

$=0.1875 \,Nm ^2 / C$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 1. Electric charges and fields→1. Electric charges and fields — all question types→Physics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

If $i = {t^2}$ $0 < t < T$ then $r.m.s$. value of current is

One proton beam enters a magnetic field of $10^{-4}$ T normally, Specific charge = $10^{11}$C/kg. velocity = $10^7$m/s. What is the radius of the circle described by it

A nucleus of mass $M + \Delta m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $c.$ The binding energy per nucleon for the parent nucleus is $E_1$ and that for the daughter nuclei is $E_2$ . Then

The graph represents the decay of a newly prepared sample of radioactive nuclide $X$ to a stable nuclide $Y$ . The half-life of $X$ is $\tau $ . The growth curve for $Y$ intersects the decay curve for $X$ after time $T$ . What is the time $T$ ?

The correct curve between voltage gain $({A_v})$ and load resistance $({R_L})$ is

The de Broglie wavelength $\lambda$ associated with a proton increases by $25 \%$, if its momentum is decreased by $p_0$. The initial momentum was

An infinite number of electric charges each equal to $5\, nC$ (magnitude) are placed along $X$-axis at $x = 1$ $cm$, $x = 2$ $cm$ , $x = 4$ $cm$ $x = 8$ $cm$ ………. and so on. In the setup if the consecutive charges have opposite sign, then the electric field in Newton/Coulomb at $x = 0$ is $\left( {\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}\,N - {m^2}/{c^2}} \right)$

The main source of solar energy is

The wavelength of ${K_\alpha }$ line in copper is $1.54 Å$. The ionisation energy of $K$ electron in copper in Joule is

The value of current through the $20\,\Omega $ resistor is ............ $amp$