A solid aluminium sphere and a solid copper sphere of twice the r… - Vidyadip

Question

A solid aluminium sphere and a solid copper sphere of twice the radius are heated to the same temperature and are allowed to cool under identical surrounding temperatures. Assume that the emissivity of both the spheres is the same. Find the ratio of:

The rate of heat loss from the aluminium sphere to the rate of heat loss from the copper sphere.
The rate of fall of temperature of the aluminium sphere to the rate of fall of temperature of the copper sphere. The specific heat capacity of aluminium = 900Jkg^-1°C^-1and that of copper= 390Jkg^-1°C^-1. The density of copper = 3.4 times the density of aluminium.

✓

Answer

E → Energy radiated per unit area per unit time

Rate of heat flow → Energy radiated

Per time $=\text{E}\times\text{A}$

So, $\text{E}_\text{Al}=\frac{\text{e}\sigma\text{T}^4\times\text{A}}{\text{e}\sigma\text{T}^4\times\text{A}}$

$=\frac{4\pi\text{r}^2}{4\pi(2\text{r})^2}$

$=\frac{1}{4}$ $\big[\therefore1:4\big]$

Emissivity of both are same

$=\frac{\text{m}_1\text{S}_1\text{dT}_1}{\text{m}_2\text{S}_2\text{dT}_2}=1$

$\Rightarrow\frac{\text{dT}_1}{\text{dT}_2}=\frac{\text{m}_2\text{S}_2}{\text{m}_1\text{S}_1}$

$=\frac{\text{s}_14\pi\text{r}_1^3\times\text{S}_2}{\text{s}_24\pi\text{r}_2^3\times\text{S}_1}$

$=\frac{1\times\pi\times900}{3.4\times8\pi\times390}$

$=1:2:9$

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