MCQ
A spherical liquid drop of radius $R$ is divided into eight equal droplets. If surface tension is $T$, then the work done in this process will be
- A2$\pi {R^2}T$
- B3$\pi {R^2}T$
- ✓4$\pi {R^2}T$
- D2$\pi R{T^2}$
✓
Answer
Correct option: C.
4$\pi {R^2}T$
c
(c)$W = 4\pi {R^2}T({r^{1/3}} - 1) = 4\pi {R^2}T({8^{1/3}} - 1) = 4\pi {R^2}T$
(c)$W = 4\pi {R^2}T({r^{1/3}} - 1) = 4\pi {R^2}T({8^{1/3}} - 1) = 4\pi {R^2}T$
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