A spring of force constant $k$ is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of
IIT 1999, Medium
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(b) Force constant $(k) \propto \frac{1}{{{\rm{Length}}\,{\rm{of}}\,{\rm{spring}}}}$
$ \Rightarrow \frac{K}{{{K_1}}} = \frac{{{l_1}}}{l} = \frac{{\frac{2}{3}l}}{l}$
$ \Rightarrow {K_1} - \frac{3}{2}K$.
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