A spring of force constant $k$ is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of
A$(2/3)k$
B$(3/2)k$
C$3k$
D$6k$
IIT 1999, Medium
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B$(3/2)k$
b (b) Force constant $(k) \propto \frac{1}{{{\rm{Length}}\,{\rm{of}}\,{\rm{spring}}}}$
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