MCQ
A stone projected with a velocity $u$ at an angle $\theta$ with the horizontal reaches maximum height $H$. When it is projected with velocity $u$ at an angle $\left(\frac{\pi}{2}-\theta\right)$ with the horizontal, it reaches maximum height $H$. The relation between the horizontal range $R$ of the projectile, $H$ and $H$ is
- ✓$R=4 \sqrt{H_1 H_2}$
- B$R=4\left(H_1-H_2\right)$
- C$R=4\left(H_1+H_2\right)$
- D$R=\frac{H_1^2}{H_2^2}$
