MCQ
A suitable unit for gravitational constant is
  • A
    $k g-m sec ^{-1}$
  • B
    $N m^{-1} sec$
  • $N m^2 kg ^{-2}$
  • D
    $k g m sec ^{-1}$

Answer

Correct option: C.
$N m^2 kg ^{-2}$
(c) $F=\frac{G m_1 m_2}{d^2} ; \therefore G=\frac{F d^2}{m_1 m_2}=\mathrm{Nm}^2 / \mathrm{kg}^2$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free