MCQ
A telescope has large diameter of the objective. Then its resolving power is
  • A
    independent of the diameter of the objective
  • B
    low
  • C
    zero
  • high.

Answer

Correct option: D.
high.
(d) : Resolving power of telescope, $R=\frac{1}{\Delta \theta}=\frac{a}{1.22 \lambda}$, where $a$ is diameter of objective lens of the telescope.
Now, as the resolving power is directly proportional to the diameter of the objective. Thus for large diameter of the objective of the telescope its resolving power will be high.

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