MCQ
A thermo-dynamical system is changed from state $\left(P_1, V_1\right)$ to $\left(P_2, V_2\right)$ by two different process. The quantity which will remain same will be
- A$\Delta Q$
- B$\Delta W$
- C$\Delta Q+\Delta W$
- ✓$\Delta Q-\Delta W$
✓
Answer
Correct option: D.
$\Delta Q-\Delta W$
(d) Change in internal energy does not depend upon path so $\Delta U=\Delta Q-\Delta W$ remain constant.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
On mixing the salt in water, the surface tension of water will
The magnifying power of a compound microscope increases when
In C.G.S. system the magnitutde of the force is 100 dynes. In another system where the fundamental physical quantities are kilogram, metre and minute, the magnitude of the force is
The potential energy of a body is given by, $U=A-B x^2$ (Where $x$ is the displacement). The magnitude of force acting on the particle is
→A block of mass $m$, attached to a spring of spring constant $k$, oscillates on a smooth horizontal table. The other end of the spring is fixed to a wall. The block has a speed $v$ when the spring is at its natural length. Before coming to an instantaneous rest, if the block moves a distance $x$ from the mean position, then
→A potential difference of $V$ is applied at the ends of a copper wire of length $/$ and diameter $d$. On doubling only $d$, drift velocity
→From the adjacent figure, the correct observation is
Davission and Germer experiment proved
An earth satellite of mass $m$ revolves in a circular orbit at a height $h$ from the surface of the earth. $R$ is the radius of the earth and $g$ is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by
→The total energy of the body executing S.H.M. is $E$. Then the kinetic energy when the displacement is half of the amplitude, is
→