MCQ
A thermodynamic system undergoes cyclic process $A B C D A$ as shown in figure. The work done by the system is
- A$P_0 V_0$
- B$2 P_0 V_0$
- C$\frac{P_0 V_0}{2}$
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Answer
Correct option: D.
Zero
(d)$w_{\text {u. }}=-$ Area of triangle $B C O=-\frac{P_0 V_0}{2}$$W_{-m}=+$ Area of triangle $A O D=+\frac{P_0 V_0}{2}$
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