MCQ
In X-ray tube when the accelerating voltage $V$ is halved, the difference between the wavelength of $K_\alpha$ line and minimum wavelength of continuous $X$-ray spectrum
  • A
    Remains constant
  • Becomes more than two times
  • C
    Becomes half
  • D
    Becomes less than two times

Answer

Correct option: B.
Becomes more than two times
$\Delta \lambda=\lambda_{K_\alpha}-\lambda_{\min }$ When $V$ is halved $\lambda_{\min }$ becomes two times but $\lambda_{K_\alpha}$ remains the same.
$ \therefore \quad \Delta \lambda^{\prime}=\lambda_{K_\alpha}-2 \lambda_{\min }=2(\Delta \lambda)-\lambda_{K_a} $
​​​​​​​$ \therefore \quad \Delta \lambda^{\prime}<2(\Delta \lambda)​​​​​​​$

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