Question
A thin straight infinitely long conducting wire having charge density λ is enclosed by a cylindrical surface of radius r and length l, its axis coinciding with the length of the wire. Find the expression for the electric flux through the surface of the cylinder.

Answer

Charge enclosed by the cylindrical surface $\text{q} = \lambda l $

Flux $\varphi =\frac{\text{q}}{\varepsilon_{0}}$

$ = \frac{\lambda l }{\varepsilon_{0}}$

Alternate Answer

$\varphi = \oint\overrightarrow{\text{E}}.\text{d}\overrightarrow{\text{S}} = \frac{\text{q}}{\varepsilon_{0}}$

$\varphi = \frac{\lambda l }{\varepsilon_{0}}.$

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