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STD 12 -6. Electromagnetic induction — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 -6. Electromagnetic induction4 Marks
MCQ
A transformer may be used to provide maximum power transfer between two $AC$ circuits that have different impedances $Z_1$ and $Z_2. $ The ratio of turns $N_1/N_2$ needed to meet this condition is given by :-
  • A
    $\frac{N_1}{N_2}=\frac{Z_1}{Z_2}$
  • B
    $\frac{N_1}{N_2}=\frac{Z_2}{Z_1}$
  • C
    $\frac{N_1}{N_2}=\sqrt{\frac{Z_2}{Z_1}}$
  • ✓
    $\frac{N_1}{N_2}=\sqrt{\frac{Z_1}{Z_2}}$
✓

Answer

Correct option: D.
$\frac{N_1}{N_2}=\sqrt{\frac{Z_1}{Z_2}}$
d
Maximum power transfer is In the state of resonance.

$\mathrm{P}=\mathrm{VI} \cos \theta$

$\cos \theta=1$

$\mathrm{P}=\frac{\mathrm{V}_{1}^{2}}{\mathrm{Z}_{1}}$

$\frac{V_{1}^{2}}{V_{2}^{2}}=\frac{Z_{1}}{Z_{2}}$

$\frac{V_{1}}{V_{2}}=\frac{N_{1}}{N_{2}}$

[By transformer (mutual induction) ]

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