$I=n e A v$
Where I = current
$\mathrm{n}=$ charge carrier current density
$\mathrm{e}=$ charge on the carriers
$A=$ cross sectional area
$\mathrm{v}=$ drift velocity
In the above example
$l=$ current $=\mathrm{i}$
$\mathrm{n}=$ charge carrier current density $=\mathrm{p}$
$\mathrm{e}=$ charge on the carriers $=\mathrm{q}$
$A=$ cross sectional area $=s$
$\mathrm{v}=$ drift velocity $=\mathrm{v}$
hence $i=p q s v$
$\therefore v=\frac{i}{p q{s}}$


(Round off to the Nearest Integer)


$(i)$ The equivalent e.m.f. is smaller than either of the two $e.m.f.$ is
$(ii)$ The equivalent internal resistance is smaller than either of the two internal resistances