MCQ
A uniformly charged rod of length $4\,m$ and linear charge density $\lambda  = 30\,\mu C/m$ is placed as shown in figure. Calculate the $x-$ component of electric field at point $P$.
  • $36\times10^5\, N/C$
  • B
    $9\times10^5\, N/C$
  • C
    $1.8\times10^3\, N/C$
  • D
    $27\times10^5\, N/C$

Answer

Correct option: A.
$36\times10^5\, N/C$
a
$\mathrm{E}_{\mathrm{x}}=\frac{\mathrm{k} \lambda}{\mathrm{r}}\left[\cos \theta_{1}-\cos \theta_{2}\right]$

here $\theta_{1}=0$ and $\theta_{2}=53^{\circ}$

$=36 \times 10^{5} \mathrm{N} / \mathrm{C}$

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