A voltmeter having a resistance of $998\, ohms$ is connected to a cell of $e.m.f.$ $2\, volt$ and internal resistance $2\, ohm$. The error in the measurement of $e.m.f.$ will be
Diffcult
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(c) Error in measurement $=$ Actual value $-$ Measured value
Actual value $=$ $2\,V$
$i = \frac{2}{{998 + 2}} = \frac{1}{{500}}A$
Since $E = V + ir$
$==>$ $V = E - ir = 2 - \frac{1}{{500}} \times 2 = \frac{{998}}{{500}}\,V$
Measured value $ = \frac{{998}}{{500}}\,V$
$==>$ Error$ = 2 - \frac{{998}}{{500}} = 4 \times {10^{ - 3}}\,volt$
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