MCQ
ABCD is a Rhombus such that $\angle\text{ACB}= 40^\circ,$ then $\angle\text{ADB}$ is:
- A50º
- B60º
- C100º
- D40º
✓
Answer
- 50º
Solution:
In Rhombus, diagonals bisect each other right angle. By using angle sum property in any of the four triangles formed by intersection of diagonals, we get $\angle\text{CBD} = 50$ and $\angle\text{CBD} = \angle\text{ADC}$ (alternate angles).
So, $\angle\text{ADC} = 50$
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