- AAcidic
- ✓Basic
- CNeutral
- DAmphoteric
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$1.$ Boron is approximately $sp^3$ hybridized
$2.$ $B-H-B$ angle is $180^o$
$3.$ There are two terminal $B-H$ bonds for each boron atom
$4.$ There are only $12$ bonding electrons available
Of these statements
$(I)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,}
\end{array}$
$(II)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$(III)$ $\begin{array}{*{20}{c}}
\,\,{C{H_3}} \\
{|\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - COOH} \\
{|\,\,\,\,\,\,} \\
\,\,{C{H_3}\,}
\end{array}$
$(IV)$ $(CH_3-CH_2)_3C-COOH$