- ✓Hofmann bromamide reaction
- BHofmann reaction
- CFriedel-Craft's reaction
- DHinsberg reaction
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The two products formed in above reaction are -
Statements$-I :$ In Hofmann degradation reaction, the migration of only an alkyl group takes place from carbonyl carbon of the amide to the nitrogen atom.
Statement$-II :$ The group is migrated in Hofmann degradation reaction to electron deficient atom.
In the light of the above statement, choose the most appropriate answer from the options given below
For the cell $\mathrm{Cu}(\mathrm{s})\left|\mathrm{Cu}^{2+}(\mathrm{aq})(0.01 \mathrm{M}) \| \mathrm{Ag}^{+}(\mathrm{aq})(0.001 \mathrm{M})\right| \mathrm{Ag}(\mathrm{s})$ the cell potential $=.....\times 10^{-2} \mathrm{~V}$
(Round off to the Nearest Integer).
[Use: $\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059$ ]
The electrolyte $X$ is :
| Reaction | Product | |
| $I$ | $RX + AgCN$ | $RNC$ |
| $II$ | $RX + KCN$ | $RCN$ |
| $III$ | $RX + KNO_2$ | (image) |
| $IV$ | $RX + AgNO_2$ | $R-O-N = O$ |
