MCQ
Alkenes convert into alcohols by
- AHydrolysis by dil. ${H_2}S{O_4}$
- BHydration of alkene by alkaline $KMn{O_4}$
- CHydrolysis by water vapours and conc. ${H_2}S{O_4}$
- ✓Both $(b)$ and $(c)$
$\underset{\text{Ethene}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,+{{H}_{2}}O\xrightarrow{\text{Conc}\text{.}{{H}_{2}}S{{O}_{4}}}\underset{\text{Ethanol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-OH}}\,$
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$(I)$ $TeF_6$ $(II)$ $SF_6$ $(III)$ $NCl_3$ $(IV)$ $NF_3$
Choose the correct code

$C{H_3} - CH = CH - COOH\xrightarrow{{B{r_2}}}$

Reason : There is delocalisation of electrons from filled $d$ orbitals into the empty orbitals on the $CO$ ligands.