- AEthanol, dimethyl ether, methanol and propanal
- BEthanol and methanol
- CEthanol, dimethyl ether, and methanol
- DEthanol and dimethyl ether
Explanation:
Ethanol (C2H5OH) and dimethyl ether (CH3−O−CH3) have same molecular formula but different functional groups, so they are isomers.
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In the above first order reaction the initial concentration of $\mathrm{N}_{2} \mathrm{O}_{5}$ is $2.40 \times 10^{-2}\, \mathrm{~mol} \,\mathrm{~L}^{-1}$ at $318 \,K.$ The concentration of $\mathrm{N}_{2} \mathrm{O}_{5}$ after $1\, hour$ was $1.60 \times 10^{-2}\, \mathrm{~mol} \,\mathrm{~L}^{-1}$, The rate constant of the reaction at $318\, \mathrm{~K}$ is $.....\,\times 10^{-3} \mathrm{~min}^{-1}$. (Nearest integer)
[Given: $\log 3=0.477, \log 5=0.699$ ]
[Assume theat the pre-exponential factor is same in both the cases.
Given $R =8.31 \,J\, K ^{-1} \,mol ^{-1}$ ]