MCQ
Amongst the following solutions, the buffer solution is
- ✓$N{H_4}Cl + N{H_4}OH$ solution
- B$N{H_4}Cl + NaOH$ solution
- C$N{H_4}OH + HCl$ solution
- D$NaOH + HCl$ solution
✓
Answer
Correct option: A.
$N{H_4}Cl + N{H_4}OH$ solution
(a)$N{H_4}Cl$ and $N{H_4}OH$ is a buffer solution (weak base and salt of strong acid).
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The molar heat of formation of $NH_4NO_3(s)$ is $-367.54\, kJ$ and those of $N_2O(g)$ and $H_2O(l)$ are $+ 81.46 \,kJ$ and $-285.78\, kJ$ respectively at $25\,^oC$ and $1.0$ atmospheric pressure. Calculate $\Delta U$ at $25\,^oC$ for the reaction .....$kJ$
→$NH_4NO_3(s) \rightarrow N_2O(g) + 2H_2O(l)$
If we use pyrene $(CC{l_4})$ in the Riemer-Tiemann reaction in place of chloroform, the product formed is
→Hypo is used in photography because of its
Dipole moment is shown by
The order of increasing reactivity towards $HCl$ of the following compounds will be
→$(1)$ $C{H_2} = C{H_2}$
$(2)$ ${(C{H_3})_2}C = C{H_2}$
$(3)$ $C{H_3}CH = CHC{H_3}$
The $IUPAC$ name of the compound $[Figure]$ is
→The decreasing order of electrical conductivity of the following aqueous solutions is
$0.1\, M$ Formic acid $(a)$
$0.1\, M$ Acetic acid $(b)$
$0.1\, M$ Benzoic acid $(c)$
→$0.1\, M$ Formic acid $(a)$
$0.1\, M$ Acetic acid $(b)$
$0.1\, M$ Benzoic acid $(c)$
The compound that is chiral is
In which of the following salt hydrolysis takes place
In the neutral or faintly alkaline medium, $KMnO _{4}$ oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from?
→