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$A.\,\,F -CH_2\,\,CH_2\,\,COOH$
$\begin{array}{*{20}{c}}
{B.\,\,Cl - CH - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$C.\,\,F -CH_2 -COOH$
$D.\,\,Br -CH_2-CH_2 -COOH$
Correct answer is
$P : 10\ ml, 0.1\ M\ NaOH + 5\ ml, 0.1\ M\ HCl$
$Q : 10\ ml, 0.1\ M\ NaOH + 15\ ml, 0.1\ M\ CH_3COOH$
$R : 10\ ml, 0.1\ M\ NH_3 + 10\ ml, 0.1\ M\ NH_4Cl$
$S : 10\ ml, 0.05\ M\ NaF + 5\ ml, 0.1\ M\ HF$
Which of above solutions act as buffer
(Nearest integer)
[Use : Molal Freezing point depression constant of water $\left.=1.86 \,\mathrm{~K} \,\mathrm{~kg} \,\mathrm{~mol}^{-1}\right]$
Freezing Point of water $=273\, \mathrm{~K}$
Atomic masses : $\mathrm{C}: 12.0\, \mathrm{u}, \mathrm{O}: 16.0\, \mathrm{u}, \mathrm{H}: 1.0\, \mathrm{u}]$
Statement I: Both $\left[\mathrm{Co}\left(\mathrm{NH}_3\right) 6\right]^{3+}$ and $\left[\mathrm{CoF}_6\right]^3$ complexes are octahedral but differ in their magnetic behaviour.
Statement II: $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)\right]^{3+}$ is diamagnetic whereas $\left[\mathrm{CoF} \mathrm{F}_6\right]^{3-}$ is paramagnetic.
In the light of the above statements, choose the correct answer from the options given below: