MCQ
An electron is accelerated from rest through a potential difference of $V$ volt. If the de Broglie wavelength of the electron is $1.227 \times 10^{-2}\, nm ,$ the potential difference is $......V$
- ✓$10^{4}$
- B$10$
- C$10^{2}$
- D$10^{3}$
✓
Answer
Correct option: A.
$10^{4}$
a
$\lambda=1.227 \times 10^{-2} nm$
$\lambda=1.227 \times 10^{-2} nm$
$=0.1227 \mathop A\limits^o $
$\lambda=\frac{12.27}{\sqrt{ v }} \mathop A\limits^o$
$0.1227=\frac{12.27}{\sqrt{ v }} \mathop A\limits^o$
$\sqrt{ v }=10^{2} \Rightarrow v =10^{4} volt$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Two capacitors of 1mF and 2mF are connected in series, the resultant capacitance will be
50 Ω and 100 Ω resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of 100 Ω resistance is connected across 100 Ω resistor, then the reading of the voltmeter will be
The following configuration of gate is equivalent to
A circuit consists of a coil with inductance $L$ and an uncharged capacitor of capacitance $C$. The coil is in a constant uniform magnetic field such that the flux through the coil is $\phi$. At time $t=0 \,min$, the magnetic field is abruptly switched $OFF$. Let $\omega_{0}=1 / \sqrt{L C}$ and ignore the resistance of the circuit.Then,
→Radon $({R_n})$ decays into Polonium (${P_0}$) by emitting an $\alpha - $ particle with half-life of $4\, days$. A sample contains $6.4 \times {10^{10}}$ atoms of $R_n$. After $12\, days$, the number of atoms of ${R_n}$ left in the sample will be
→Three capacitors of capacitance $3\,\mu \,F,\,10\,\mu \,F\,$ and $15\,\mu \,F\,$ are connected in series to a voltage source of $100\,V$. The charge on $15\,\mu \,F\,$is.......$\mu C$
→Energy of the electron in $n^{\text {th }}$ orbit of hydrogen atom is given by $E_n=-\frac{13.6}{n^2} e V$. The amount of energy needed to transfer electron from first orbit to third orbit is
→In the circuit shown the variable resistance is so adjusted that the ammeter reading is same in both the position $1$ and $2$ of the key. The reading of ammeter is $2A$. If $E = 20V$, then $x$ is :- ................... $\Omega$
→The two metallic plates of radius $r$ are placed at a distance $d$ apart and its capacity is $C$. If a plate of radius $r/2$ and thickness $d$ of dielectric constant $6$ is placed between the plates of the condenser, then its capacity will be
→The activity of a radioactive sample