MCQ
The following configuration of gate is equivalent to
- A$NAND$
- ✓$XOR$
- C$OR$
- D$NOR$
✓
Answer
Correct option: B.
$XOR$
b
(b)$Y = (A + B).\overline {AB} $
The given output equation can also be written as
$Y = (A + B).(\bar A + \bar B)$(De morgan’s theorem)
$ = A\bar A + A\bar B + B\bar A + B\bar B = 0 + A\bar B + \bar AB + 0 = \bar AB + A\bar B$
This is the expression for $XOR$ gate.
(b)$Y = (A + B).\overline {AB} $
The given output equation can also be written as
$Y = (A + B).(\bar A + \bar B)$(De morgan’s theorem)
$ = A\bar A + A\bar B + B\bar A + B\bar B = 0 + A\bar B + \bar AB + 0 = \bar AB + A\bar B$
This is the expression for $XOR$ gate.
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