An insulating pipe of cross-section area $'A'$ contains an electrolyte which has two types of ions $\rightarrow$ their charges being $-e$ and $+2e$. $A$ potential difference applied between the ends of the pipe result in the drifting of the two types of ions, having drift speed $= v$ ($-ve$ ion) and $v/4$ ($+ve$ ion). Both ions have the same number per unit volume $= n$. The current flowing through the pipe is
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We have two types of charges $-e$ and $+ 2 e$
When a potential different is applied both the charges drift in opposite directions.
$\therefore \mathrm{i}=\mathrm{neV}_{\mathrm{d} \mathrm{A}}$
$i_{(+v e)}=(n)(2 e) \frac{\left(V_{d}\right)}{4} A=\frac{n e V_{d} A}{2}$
$\mathrm{i}_{(-\mathrm{e})}=\mathrm{n}(-\mathrm{e})\left(-\mathrm{V}_{\mathrm{d}}\right), \mathrm{A}=\mathrm{n}_{\mathrm{e}} \mathrm{V}_{\mathrm{d}} \mathrm{A}$
$i_{total}$ $=i+2 e+i-e$
$i=\frac{3}{2} n e V_{d} A$
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