MCQ
An object is located in a fixed position in front of a screen. Sharp image is obtained on the screen for two positions of a thin lens separated by $10\, cm$. The size of the images in two situations are in the ratio $3 : 2$. What is the distance between the screen and the object?......$cm$
  • A
    $124.5$
  • B
    $144.5$
  • C
    $65$
  • $99$

Answer

Correct option: D.
$99$
d
Given: Separation of lens for two of its position, $d=10 \mathrm{cm}$

Ratio of size of the images in two positions

$\frac{I_{1}}{I_{2}}=\frac{3}{2}$

Distance of object from the screen, $D=?$

Applying formula,

${\frac{{{I_1}}}{{{I_2}}} = \frac{{{{(D + d)}^2}}}{{{{(D - d)}^2}}}}$

${ \Rightarrow \,\,\frac{3}{2} = \frac{{{{(D + 10)}^2}}}{{{{(D - 10)}^2}}}}$

${ \Rightarrow \quad \frac{3}{2} = \frac{{{D^2} + 100 + 20D}}{{{D^2} + 100 - 20D}}}$

$\Rightarrow 3 D^{2}+300-60 D=2 D^{2}+200+40 D$

$\Rightarrow \quad D^{2}-100 D+100=0$

On solving, we get $D=99\, \mathrm{cm}$

Hence the distance between the screen and the object is $99\, \mathrm{cm} .$

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