An organic compound undergoes first order decompostion. The time … - Vidyadip

MCQ

An organic compound undergoes first order decompostion. The time taken for its decomposition to $\frac{1}{8}$ and $\frac{1}{10}$ of its initial concentration are $t_{1/8}$ and $t_{1/10}$ respectively. What is the value of $\frac{{{t_{1/8}}}}{{{t_{1/10}}}}$ ? $[\log\, 2 = 0.30]$

A
$0.09$
✓
$0.9$
C
$9$
D
$90$

✓

Answer

Correct option: B.

$0.9$

b
$\mathrm{kt}_{1 / 8}=2.303 \log \frac{\mathrm{a}}{\mathrm{a} / 8}$

$\mathrm{kt}_{1 / 10}=2.303 \log \frac{\mathrm{a}}{\mathrm{a} / 10}$

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