Question
$\angle ACD$ એ $\triangle ABC$ નો બહિષ્કોણ છે. જો $\triangle ABC$ માં $\angle A = 50^{\circ}$ અને $\angle C = 40^{\circ}$ હોય, તો $\angle ACD = \dots$ ($90^{\circ}, 140^{\circ}, 150^{\circ}$)

Answer

$\angle ACD = 180^{\circ} - \angle C = 180^{\circ} - 40^{\circ} = 140^{\circ}$

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