MCQ
Angle between two curves ${y^2} = 4(x + 1)$ and ${x^2} = 4(y + 1)$ is .............. $^\circ$
- A$0$
- ✓$90$
- C$60$
- D$30$
therefore angle between them is ${90^o}$.
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Match each entry in $List-I$ to the correct entry in $List-II$.
| $List-I$ | $List-II$ |
| ($P$) $\gamma$ equals | ($1$) $-\hat{i}-\hat{j}+\hat{k}$ |
| ($Q$) A possible choice for $\hat{n}$ is | ($2$) $\sqrt{\frac{3}{2}}$ |
| ($R$) $\overline{O R_1}$ equals | ($3$) $1$ |
| ($S$) A possible value of $\overline{O R_1} \cdot \hat{n}$ is | ($4$) $\frac{1}{\sqrt{6}} \hat{i}-\frac{2}{\sqrt{6}} \hat{j}+\frac{1}{\sqrt{6}} \hat{k}$ |
| ($5$) $\sqrt{\frac{2}{3}}$ |
The correct option is
$\overrightarrow{ a }=\hat{ i }+\hat{ j }+ n \hat{ k }, \quad \overrightarrow{ b }=2 \hat{ i }+4 \hat{ j }- n \hat{ k } \quad$ and $\overrightarrow{ c }=\hat{ i }+ n \hat{ j }+3 \hat{ k } \quad( n \geq 0),$ is $158 cu. Units$, then