Question
Answer the following:
  1. In what way is diffraction from each slit related to the interference pattern in a double slit experiment?
  2. When a tiny circular obstacle is placed in the path of light from a distant source, a bright spot is seen at the centre of the shadow of the obstacle. Explain, why.
  3. How does the resolving power of a microscope depend on (i) the wavelength of the light used and (ii) the medium used between the object and the objective lens?

Answer

The intensity of interference fringes in double slit arrangement is modulated by the diffraction pattern of each slit.
Alternate Answer
In double slit experiment, the interference pattern on the screen is actually superposition of single slit diffraction for each slit.
Waves diffracted from the edges of the circular obstacle interfere constructively at the centre of the shadow producing a bright spot.
Resolving power $\frac{2\mu\sin\theta}{1.22\lambda}.$
$\therefore$ Resolving power is inversely proportional to wavelength and directly proportional to the refractive index.

Alternate Answer
  1. $\text{R.P}\propto\frac{1}{\lambda}$.
  2. $\text{R.P}\propto\mu$.

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