As shown in the figure, the voltmeter reads 2,V across 5,Omega resistor. The resistance of the voltmeter is .......,Omega.

Q: As shown in the figure, the voltmeter reads $2\,V$ across $5\,\Omega$ resistor. The resistance of the voltmeter is $.......\,\Omega$.

c $i_1=\frac{2\,V}{5\,\Omega}=\frac{2}{5}\,A$ $i=\frac{1 V}{2 \Omega}=\frac{1}{2}\,A$ $\therefore \text { Current through voltmeter }=i-i_1$ $=\frac{1}{2}-\frac{2}{5}=\frac{5-4}{10}=\frac{1}{10}\,A$ $\therefore \text { For voltmeter }$ $2=\left(\frac{1}{10}\right) R \Rightarrow R=20\,\Omega$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

As shown in the figure, the voltmeter reads $2\,V$ across $5\,\Omega$ resistor. The resistance of the voltmeter is $.......\,\Omega$.

A$18$
B$17$
C$20$
D$19$

JEE MAIN 2023, Diffcult

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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