Question
At what temperature will oxygen molecules have same rms speed as helium molecules at S.T.P.? (Molecular masses of oxygen and helium are 32 and 4 respectively)

Answer

Data: $T_2=273 K , M_{01}$ (oxygen) $=32 \times 10^{-3} kg / mol , M_{02}$ (hydrogen) $=4 \times 10^{-3} kg / mol$ The rms speed of oxygen molecules, $v _1=\sqrt{\frac{3 R T_1}{M_{01}}}$ and that of helium molecules, $v _2=$ $\sqrt{\frac{3 R T_2}{M_{02}}}$
When $v _1= v _2$
$
\sqrt{\frac{3 R T_1}{M_{01}}}=\sqrt{\frac{3 R T_2}{M_{02}}}
$
$\therefore \frac{T_1}{M_{01}}=\frac{T_2}{M_{02}}$
$\therefore$ Temperature, $\begin{aligned} T_1 & =\frac{M_{01}}{M_{02}} \cdot T_2=\frac{\left(32 \times 10^{-3}\right)(273)}{4 \times 10^{-3}} \\ & =2184 K \end{aligned}$

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