MCQ
Azo dye is prepared by the coupling of phenol and :
- ✓Diazonium chloride
- B$o-$nitro aniline
- CBenzoic acid
- DChlorobenzene

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$C{{H}_{3}}-C\equiv CH\xrightarrow[{{H}_{2}}S{{O}_{4}}]{HgS{{O}_{4}}}A\xrightarrow{NaB{{H}_{4}}}B$
$(i)$ $PCl_3 + 3H_2O \to H_3PO_3 + 3HCl$
$(ii)$ $SF_4 + 3H_2O \to H_3SO_3 + 4HF$
$(iii)$ $BCI_3 + 3H_2O \to H_3BO_3 + 3HCl$
$(IV)$ $XeF_6 + 3H_2O \to XeO_3 + 6HF$
Then according to given information the incorrect statement is
$\xrightarrow[{{H_2}O}]{{B{r_2}}}$
