BeCl _ 2 reacts with LiAlH _ 4 to give .... - Vidyadip

MCQ

$BeCl _{2}$ reacts with $LiAlH _{4}$ to give ....

A
$Be + Li \left[ AlCl _{4}\right]+ H _{2}$
B
$Be + AlH _{3}+ LiCl + HCl$
✓
$BeH _{2}+ LiCl + AlCl _{3}$
D
$BeH _{2}+ Li \left[ AlCl _{4}\right]$

✓

Answer

Correct option: C.

$BeH _{2}+ LiCl + AlCl _{3}$

c
$2 BeCl _{2}+ LiAlH _{4} \rightarrow 2 BeH _{2}+ LiCl + AlCl _{3}$

This is the method to prepare $BeH _{2}$

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