MCQ
Benzaldehyde and acetaldehyde can be differentiated by
- A$HCN$
- B$N{H_2}OH$
- C$Hydrazine$
- ✓$NaOH$ solution

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| List $I$ Oxide | List $II$ Type of Bond |
| $A$ $N _2 O _4$ | $I$. $1 N = O$ bond |
| $B$ $NO _2$ | $II$. $1 N - O - N$ bond |
| $C$ $N _2 O _5$ | $III$. $1 N - N$ bond |
| $D$ $N _2 O$ | $IV$. $1 N = N / N \equiv N$ bond |
Choose the correct answer from the options given below:

$Fe ^{2+} \rightarrow Fe ^{3+} + e ^{-} \quad E _{ Fe ^{3+} / Fe ^{2+}}=0.77 \,V$
$2 I ^{-} \rightarrow I _{2}+2 e ^{-} \quad E _{ I _{2} / I ^{-}}^{0}=0.54 \,V$
The standard electrode potential for the spontaneous reaction in the cell is $x \times 10^{-2} \,V 298$ $K$. The value of $x$ is .... (Nearest Integer)